Chalk−1

Math · College algebra · Worked example

Solve a compound inequality

Solve −1 < 5 − 2x ≤ 9 and write the answer in interval notation.

−1<5−2⁢x≤9

Work on all three parts at once

A three-part inequality is an “and” statement: 5 − 2x must be greater than −1 and at most 9. Whatever you do to the middle, do to both outer parts. Subtract 5 from all three.

−6<−2⁢x≤4

Divide by −2 and reverse both signs

Dividing every part by −2 reverses both inequality signs: −6 ÷ (−2) = 3 and 4 ÷ (−2) = −2.

3>x≥−2

Rewrite from smallest to largest

Read the same statement from right to left so the smaller number comes first. The endpoint −2 is included, because of ≥, and 3 is left out.

−2≤x<3

Write the interval and check

The interval is [−2, 3). Check x = 0: 5 − 0 = 5, and −1 < 5 ≤ 9 is true. Check x = 3: 5 − 6 = −1, and −1 < −1 is false, so 3 stays out.

x∈[−2,3)

Result

−2 ≤ x < 3, which is [−2, 3).

x∈[−2,3)

Your turn

Solve 1 ≤ (3 − x)/2 < 4 and write the answer in interval notation.

Show the answer and explanation

−5 < x ≤ 1, which is (−5, 1].

Multiply all three parts by 2: 2 ≤ 3 − x < 8. Subtract 3: −1 ≤ −x < 5. Multiply by −1 and reverse both signs: 1 ≥ x > −5, which reads −5 < x ≤ 1.

1≤3−x2<42≤3−x<8−1≤−x<5−5<x≤1

Keep exploring

Open the steps in Math and leave the signs unreversed after dividing by −2: the checker marks that line ✗.

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