Chalk−1

Chemistry · General chemistry II · Worked example

Find a concentration from a calibration curve

Standards of a dye give the absorbances below. An unknown sample reads A = 0.350. Find its concentration.

Tabulate the standards

Each standard pairs a known concentration with its measured absorbance at the same wavelength.

Calibration standards
c (µmol/L)02.004.006.008.00
A0.0020.1510.3020.4490.601

Fit a straight line

A least-squares line through the five points has slope 0.0748 per µmol/L and intercept 0.0018. It fits closely: R² = 0.99998, and no point lies more than 0.002 from the line.

A=0.0748⁢c+0.0018

Solve for the unknown

Set A = 0.350 and solve for c.

c=0.350−0.00180.0748=4.66 μ⁢mol/L

Check the range

The unknown’s absorbance, 0.350, lies inside the range of the standards, 0.002 to 0.601, so reading it from the line is justified.

Result

About 4.66 µmol/L.

Your turn

Another sample reads A = 0.525 on the same line. Find its concentration.

Show the answer and explanation

6.99 µmol/L.

c = (0.525 − 0.0018)/0.0748 = 6.99 µmol/L. Its absorbance is still inside the range of the standards.

c=0.525−0.00180.0748=6.99 μ⁢mol/L

Keep exploring

In Photons & spectrophotometry, set the dilution factor to 10, as if the sample had been diluted tenfold before measuring. The original sample is 46.6 µmol/L.

Return to the concept →
Sources and scope

Authored study material. Tool results depend on the stated inputs and model assumptions.

Make it concrete

Try in the workspace

Open the example inputs, change a value and keep a useful result on your board.

Fit it in Photons & spectrophotometry Open worked example on a board Chemistry formulas: organic (Beer–Lambert law)

Your existing work stays on this device. Examples open as editable copies.