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Math · Calculus I · Worked example

Apply Rolle’s theorem

Check that Rolle’s theorem applies to f(x) = x³ − 4x on [−2, 2], and find every c it promises.

f⁡(x)=x3−4⁢x

Check the conditions

f is a polynomial, so it is continuous and differentiable everywhere, and its endpoint values are equal.

(−2)3−4⁢(−2)=023−4⋅2=0

Solve f′(c) = 0

f′(x) = 3x² − 4.

3c2−4=0c2=43

Both values count

c = ±2/√3 ≈ ±1.155, and both lie in (−2, 2): the graph has a local maximum and a local minimum there. The theorem promises at least one c; here there are two.

Result

c = −2/√3 and c = 2/√3, about ±1.155.

Your turn

Find the c from Rolle’s theorem for f(x) = x² − 6x + 5 on [1, 5].

Show the answer and explanation

c = 3.

f(1) = 0 = f(5), and f′(c) = 2c − 6 = 0 gives c = 3.

12−6⋅1+5=052−6⋅5+5=0

Keep exploring

In Graph, the two horizontal tangents sit at the turning points, near (−1.155, 3.079) and (1.155, −3.079).

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