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Chemistry · General chemistry II · Concept

Activation energy from Arrhenius plots

Use rate constants measured at several temperatures to find the activation energy Ea and the frequency factor A from an Arrhenius plot, or Ea from two temperatures with the two-point form.

What the Arrhenius equation says

Rate constants grow with temperature because more collisions carry enough energy to cross the barrier. The Arrhenius equation splits k into two factors. The frequency factor A counts how often reactants approach the barrier with a suitable orientation, and has the same units as k. The exponential factor e^(−Ea/RT) is the fraction of those approaches with enough energy. It is tiny when Ea is many times RT, which is why a modest temperature rise can multiply k several times.

k=Ae−Ea/⁢R⁢T

Make it a straight line

Taking the natural logarithm turns the equation into y = mx + b, with y = ln k and x = 1/T. Plot ln k against 1/T: the slope is −Ea/R and the intercept is ln A. Multiplying the slope by −R gives Ea; raising e to the intercept gives A.

lnk=−EaR(1T)+lnA
Reading an Arrhenius plot
Plot featureEqualsSo
x-axis1/T (K⁻¹)Temperatures must be in kelvin
y-axisln kKeep one set of k units
Slope−Ea/REa = −slope × 8.314 J/(mol·K)
Interceptln AA = e^intercept, in the units of k

Two temperatures: the two-point form

With only two rate constants, write the Arrhenius equation at each temperature and subtract. ln A cancels, leaving an equation you can solve for Ea, or for a rate constant at a new temperature once Ea is known. Two points always lie on a line, so this gives no check on whether a single Ea really fits.

lnk2k1=EaR(1T1−1T2)

Units, precision and what the fit means

Use R = 8.314 J/(mol·K) and temperatures in kelvin, then convert Ea to kJ/mol. A is an extrapolation to 1/T = 0, far outside any measured range, so it is much less precise than Ea: report it to one or two significant figures. A straight Arrhenius plot supports one roughly constant Ea over that temperature range. A curved one suggests the mechanism or rate-limiting step changes with temperature.

Why A carries the units of k

The exponential factor is dimensionless, so A must have the same units as k. For a first-order reaction that is s⁻¹; for a second-order reaction, M⁻¹ s⁻¹. In the collision model A = pz: an orientation factor p times a collision frequency z.

A=pz

Common mistakes

  • Plotting k instead of ln k, or T instead of 1/T.
  • Using temperatures in °C.
  • Reporting the slope itself as Ea, instead of −R × slope.
  • Mixing R = 8.314 J/(mol·K) with Ea in kJ/mol without converting.
  • Quoting A to as many figures as Ea.
  • Assuming a 10 K rise always doubles k: the factor depends on Ea and T.

Key terms

Arrhenius equation
k = A·e^(−Ea/RT): how a rate constant grows with temperature. A plot of ln k against 1/T is a line with slope −Ea/R, which gives the activation energy.
Frequency factor
The factor A in the Arrhenius equation k = A·e^(−Ea/RT): how often reactant molecules collide with the right orientation.
Exponential factor
The term e^(−Ea/RT) in the Arrhenius equation: the fraction of collisions with enough energy to get over the activation barrier. It grows as the temperature rises.
Rate law
An equation linking reaction rate to reactant concentrations, such as rate = k[A]²[B]. The units of the rate constant k depend on the overall order.

Work through an example

A first-order reaction has these rate constants at four temperatures. Find the activation energy and the frequency factor.

Find Ea and A from an Arrhenius plot →

Find Ea from two rate constants →

Sources and scope

Authored study material. Tool results depend on the stated inputs and model assumptions.

  • Tro, Chemistry: A Molecular Approach, 4th ed., §14.5 The Effect of Temperature on Reaction Rate, pp. 642–647 (Arrhenius plots, pp. 644–645; two-point form, p. 646)
  • OpenStax Chemistry 2e — Collision theory
Make it concrete

Try in the workspace

Open the example inputs, change a value and keep a useful result on your board.

Fit the Arrhenius plot in Kinetics See what Ea does to energetic collisions Open worked example on a board Chemistry formulas: experimental analysis

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